COMEDK · Chemistry · 19. Chemical Kinetics
The rate constant for a First order reaction at \(560 \mathrm{~K}\) is \(1.5 \times 10^{-6}\) per second. If the reaction is allowed to take place for 20 hours, what percentage of the initial concentration would have converted to products?
- A 10.23
- B 21.2
- C 11.14
- D 12.46
Answer & Solution
Correct Answer
(A) 10.23
Step-by-step Solution
Detailed explanation
For a first order reaction, the integrated rate equation is given by \(k = \dfrac{2.303}{t} \log \left( \dfrac{[A]_0}{[A]_t} \right)\). Given values are \(k = 1.5 \times 10^{-6} \text{ s}^{-1}\) and \(t = 20 \text{ hours} = 20 \times 3600 \text{ s} = 72000 \text{ s}\).…
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