COMEDK · Chemistry · 9. Redox Reactions
The oxidation number of oxygen is \(-1\) in
- A \(\mathrm{NO}_{2}\)
- B \(\mathrm{PbO}_{2}\)
- C \(\mathrm{Na}_{2} \mathrm{O}_{2}\)
- D \(\mathrm{MnO}_{2}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Na}_{2} \mathrm{O}_{2}\)
Step-by-step Solution
Detailed explanation
General oxidation state of oxygen is \((-2)\). But in peroxide, it's oxidation state is \((-1)\). \(\therefore\) The oxidation number of oxygen is \(-1\) in \(\mathrm{Na}_{2} \mathrm{O}_{2}\). \(2 \times 1+2 x=0\) \(x=-1\)
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