COMEDK · Chemistry · 24. Coordination Compounds
The oxidation number of oxygen in \(\mathrm{CO}_3\) and \(\mathrm{Na}_2 \mathrm{O}_2\) is
- A 3,2
- B 1,0
- C 0,1
- D \(-0.33,-1\)
Answer & Solution
Correct Answer
(D) \(-0.33,-1\)
Step-by-step Solution
Detailed explanation
Let oxidation number of oxygen \(=x\) O.N. of oxygen in \(\mathrm{CO}_3=1+3 x=0\) \(\therefore \quad x=\frac{-1}{3}\) or -0.33 Oxidation number of oxygen in \(\mathrm{Na}_2 \mathrm{O}_2\) \(\begin{aligned} & =2 \times 1+2 x=0 \\ & \therefore \quad x=-1 \end{aligned}\)
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