COMEDK · Chemistry · 24. Coordination Compounds
The number of geometrical isomers in the following metal complexes \(\mathrm{Ni}(\mathrm{CO})_4,\left[\mathrm{Ru}\left(\mathrm{H}_2 \mathrm{O}\right)_3 \mathrm{Cl}_3\right],\left[\mathrm{CuCl}_2\left(\mathrm{NH}_3\right)_4\right]^{+}\)and \(\left[\mathrm{PtCl}_2\left(\mathrm{NH}_3\right)_2\right]\) are
- A \(1,0,2,2\)
- B \(0,2,2,2\)
- C \(2,0,0,2\)
- D \(2,0,2,2\)
Answer & Solution
Correct Answer
(B) \(0,2,2,2\)
Step-by-step Solution
Detailed explanation
The complex \(\mathrm{Ni}(\mathrm{CO})_4\) is a tetrahedral complex of the type \(MA_4\). Tetrahedral complexes of the type \(MA_4\) or \(MA_3B\) do not exhibit geometrical isomerism. Thus, the number of geometrical isomers is \(0\). The complex…
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