COMEDK · Chemistry · 4. Chemical Bonding and Molecular Structure
The number of antibonding electron pairs in \(\mathrm{O}_{2}^{2-}\) molecular ion on the basis of molecular orbital theory is
[Atomic number of \(\mathrm{O}\) is 18 ]
- A 2
- B 3
- C 4
- D 5
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
Configuration of \(\mathrm{O}_{2}^{2-}=\sigma 1 s^{2}, \sigma^{n} 1 s^{2}, \sigma 2 s^{2}, \sigma^{n} 2 s^{2}\), \(\sigma 2 p_{x}^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi^{4} 2 p_{x}^{2} \approx \pi \pi_{p}^{2}\). \(\therefore\) Number of antibonding electron pairs is…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- The equilibrium constants for the reactions \(a, b\), and \(c\) are as given:
a) \(\mathrm{N}_2+3 \mathrm{H}_2=2 \mathrm{NH}_3: \mathbf{K}_1\)
b) \(\mathrm{N}_2+\mathrm{O}_2=2 \mathrm{NO}: \mathrm{K}_2\)
c) \(2 \mathrm{H}_2+\mathrm{O}_2=2 \mathrm{H}_2 \mathrm{O}: \mathbf{K}_3\)
What would be the Equilibrium constant for the reaction:
\(4 \mathrm{NH}_3+5 \mathrm{O}_2=4 \mathrm{NO}+6 \mathrm{H}_2 \mathrm{O} ; \mathbf{K}_{\mathbf{x}}\)COMEDK 2023 Medium - Given below are 4 species with one odd electron on the Carbon atom.
\(\begin{array}{ll}
\mathrm{A}=\left(\mathrm{CH}_3\right)_3 \stackrel{\bullet}{\mathrm{C}} & \mathrm{B}=\left(\mathrm{C}_6 \mathrm{H}_5\right)_3 \stackrel{\bullet}{\mathrm{C}} \\
\mathrm{C}=\left(\mathrm{C}_6 \mathrm{H}_5\right)_2 \stackrel{\bullet}{\mathrm{C}} \mathrm{H} & \mathrm{D}=\left(\mathrm{CH}_3\right)_2 \stackrel{\bullet}{\mathrm{C}} \mathrm{H}
\end{array}
\)
Choose the correct decreasing order of stability of the species.COMEDK 2024 Medium - The rate constants for two different reactions, \(k_1\) and \(k_2\) are \(10^{16}\cdot e^{-2000/T}\) and \(10^{15}\cdot e^{-1000/T}\) respectively. The temperature at which \(k_1 = k_2\) isCOMEDK 2026 Medium
- Which one of the following statements is correct?COMEDK 2025 Medium
- The equilibrium constant of given reaction is 100 .
\(\mathrm{N}_2(\mathrm{~g})+2 \mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_2\) (gas)
What is the equilibrium constant for the reaction given below?
\(\mathrm{NO}_2(g) \rightleftharpoons \frac{1}{2} \mathrm{~N}_2(g)+\mathrm{O}_2(g)\)COMEDK 2024 Hard - Which of the following is not an amphoteric substance?COMEDK 2016 Medium
More PYQs from COMEDK
- An object of mass \(1 \mathrm{~kg}\) is allowed to hang tangentially from the rim of the wheel of radius R. When released from the rest, the block falls vertically through \(4 \mathrm{~m}\) height in 2 seconds. The moment of inertia is \(1 \mathrm{~kg} \mathrm{~m}^2\). The radius of the wheel \(\mathrm{R}\) is
COMEDK 2024 Medium - Identify the final product formed when benzenamine reacts with the given reagents in the sequential order as:
i. (CH\(_3$$-\)CO )\(_2\)O / Pyridine.
ii. Conc. HNO\(_3\) + H\(_2\)SO\(_4\) & then reacted with H\(_3\)O\(^+\)
iii. NaNO\(_2\) HCl (273K) & then reacted with H\(_3\)PO\(_2\)(aq).COMEDK 2026 Hard - Using the data given below, the strongest reducing agent is:
\(E^o_{\text{Cr}_2\text{O}_7^{2-}/\text{Cr}^{3+}} = 1.33\) V \(E^o_{\text{MnO}_4^-/\text{Mn}^{2+}} = 1.51\) V
\(E^o_{\text{Cl}_2/\text{Cl}^-} = 1.36\) V \(E^o_{\text{Cr}^{3+}/\text{Cr}} = -0.74\) VCOMEDK 2026 Medium - At \(300 \mathrm{~K}\), the half-life period of a gaseous reaction at an initial pressure of \(40 \mathrm{~kPa}\) is 350 s. When pressure is \(20 \mathrm{~kPa}\), the half-life period is 175 s. What is the order of the reaction?COMEDK 2023 Medium
- The total number of numbers greater than 1000 but less than 4000 that can be formed using 0,2,3,4 (using repetition allowed) areCOMEDK 2023 Easy
- If \(f(x)=\log _{x^{2}}(\log x)\), then \(f^{\prime}(x)\) at \(x=e\) isCOMEDK 2015 Easy