COMEDK · Chemistry · 17. Solutions
The mole fraction of an unknown solute in 1560 g of Benzene is 0.5 . What is the molality of the solution? (M. M of Benzene:78 amu)
- A \(3.25\)
- B \(16.9\)
- C \(12.8\)
- D \(10.3\)
Answer & Solution
Correct Answer
(C) \(12.8\)
Step-by-step Solution
Detailed explanation
Let \(n_B\) be the number of moles of Benzene and \(n_S\) be the number of moles of solute. The mass of Benzene is \(1560\) g and its molar mass is \(78\) g/mol. Thus, \(n_B = \dfrac{1560}{78} = 20\) moles. The mole fraction of the solute is given as \(x_S = 0.5\). Since…
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