COMEDK · Chemistry · 18. Electrochemistry
The Molar conductivity of \(0.05 \mathrm{M}\) solution of \(\mathrm{MgCl}_2\) is \(194.5 \mathrm{~ohm}^{-1} \mathrm{~cm}^2\) per mole at room temperature. A Conductivity cell with electrodes having \(3.0 \mathrm{~cm}^2\) surface area and \(1.0 \mathrm{~cm}\) apart is filled with the solution of \(\mathrm{MgCl}_2\). What would be the resistance offered by the conductivity cell?
- A 402.6 ohms
- B 34.27 ohms
- C 0.00291 ohms
- D 114.25 ohms
Answer & Solution
Correct Answer
(B) 34.27 ohms
Step-by-step Solution
Detailed explanation
The molar conductivity \(\Lambda_m\) is related to the conductivity \(\kappa\) and molarity \(C\) by the formula \(\Lambda_m = \dfrac{1000 \times \kappa}{C}\). Given \(\Lambda_m = 194.5 \text{ ohm}^{-1} \text{ cm}^2 \text{ mol}^{-1}\) and \(C = 0.05 \text{ M}\), we calculate the…
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