COMEDK · Chemistry · 1. Some Basic Concepts of Chemistry
The mass of glucose to be dissolved in \(50 \mathrm{~g}\) of water to get \(0.3\) molal solution is
- A \(27 \mathrm{~g}\)
- B \(0.27 \mathrm{~g}\)
- C \(2.7 \mathrm{~g}\)
- D \(5.4 \mathrm{~g}\)
Answer & Solution
Correct Answer
(C) \(2.7 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
Molecular mass of glucose \(=180 \mathrm{~g} / \mathrm{mol}\) Mass of water \(=50 \mathrm{~g}=0.05 \mathrm{~kg}\) Molality \((m)=\frac{\text { Mass }}{\text { Molar mass } \times \text { mass of solvent }(\text { in kg) }}\) \(0.3=\frac{\text { Mass }}{160 \times 0.05}\) Mass…
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