COMEDK · Chemistry · 23. d and f Block Elements
The ion that has a spin only magnetic moment of 5.9 BM is:
- A \(\text{Fe}^{3+}\)
- B \(\text{Ni}^{2+}\)
- C \(\text{Mn}^{3+}\)
- D \(\text{Co}^{3+}\)
Answer & Solution
Correct Answer
(A) \(\text{Fe}^{3+}\)
Step-by-step Solution
Detailed explanation
The spin-only magnetic moment is given by the formula \(\mu = \sqrt{n(n+2)}\) BM, where \(n\) is the number of unpaired electrons. Given \(\mu = 5.9\) BM, we have \(\sqrt{n(n+2)} = 5.9\). Squaring both sides gives \(n(n+2) \approx 35\), which corresponds to \(n = 5\) unpaired…
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