COMEDK · Chemistry · 18. Electrochemistry
The \(\Delta\)G\(^o\) for the reaction, \(\text{Cd}^{2+}(aq) + \text{Zn}(s) \rightarrow \text{Zn}^{2+}(aq) + \text{Cd}(s)\) is:
\(\left[E^o_{\text{Cd}^{2+}/\text{Cd}} = -0.403,\ E^o_{\text{Zn}^{2+}/\text{Zn}} = -0.763\ V\right]\)
- A \(-72.2\ kJ\)
- B \(-69.5\ kJ\)
- C \(-50\ kJ\)
- D \(-44.5\ kJ\)
Answer & Solution
Correct Answer
(B) \(-69.5\ kJ\)
Step-by-step Solution
Detailed explanation
For the reaction \(\text{Cd}^{2+}(aq) + \text{Zn}(s) \rightarrow \text{Zn}^{2+}(aq) + \text{Cd}(s)\), Zn is oxidized (anode) and \(\text{Cd}^{2+}\) is reduced (cathode). \(E^{\circ}_{\text{cell}} = E^{\circ}_{\text{cathode}} - E^{\circ}_{\text{anode}}\)…
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