COMEDK · Chemistry · 2. Structure of Atom

The frequency of photon which is emitted during a transition of electron of He\(^+\) ion from fifth energy level to third energy level will be:

A \(9.39 \times 10^{14}\ s^{-1}\)
B \(1.34 \times 10^{-14}\ s^{-1}\)
C \(2.34 \times 10^{14}\ s^{-1}\)
D \(8.29 \times 10^{-14}\ s^{-1}\)

Verified Solution

Answer & Solution

Correct Answer

(A) \(9.39 \times 10^{14}\ s^{-1}\)

Step-by-step Solution

Detailed explanation

Using the Rydberg formula for the frequency of the emitted photon: \(\nu = R c Z^2 \left( \dfrac{1}{n_1^2} - \dfrac{1}{n_2^2} \right)\) For the He\(^+\) ion, \(Z = 2\). The transition is from \(n_2 = 5\) to \(n_1 = 3\).…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

No.	Vitamin	No.	Deficiency
A	K	P	Cheilosis
B	\(B_{12}\)	Q	Osteomalacia
C	\(B_2\)	R	Permicious Anaemia
D	D	S	Haemophilia

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