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COMEDK · Chemistry · 22. p Block Elements (Group 15, 16, 17 & 18)

The formation of \(\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}\)is basis for the formation of xenon fluorides. This is because

  1. A \(\mathrm{O}_{2}\) and Xe have comparable sizes
  2. B Both \(\mathrm{O}_{2}\) and \(\mathrm{Xe}\) are gases
  3. C \(\mathrm{O}_{2}\) and Xe have comparable ionisation energies
  4. D \(\mathrm{O}_{2}\) and Xe have comparable electronegativities
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{O}_{2}\) and Xe have comparable ionisation energies

Step-by-step Solution

Detailed explanation

The formation of \(\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}\)is the basis for the formation of xenon fluorides because \(\mathrm{O}_{2}\) and \(\mathrm{Xe}\) have - comparable ionisation energies.