COMEDK · Chemistry · 22. p Block Elements (Group 15, 16, 17 & 18)
The formation of \(\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}\)is basis for the formation of xenon fluorides. This is because
- A \(\mathrm{O}_{2}\) and Xe have comparable sizes
- B Both \(\mathrm{O}_{2}\) and \(\mathrm{Xe}\) are gases
- C \(\mathrm{O}_{2}\) and Xe have comparable ionisation energies
- D \(\mathrm{O}_{2}\) and Xe have comparable electronegativities
Answer & Solution
Correct Answer
(C) \(\mathrm{O}_{2}\) and Xe have comparable ionisation energies
Step-by-step Solution
Detailed explanation
The formation of \(\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}\)is the basis for the formation of xenon fluorides because \(\mathrm{O}_{2}\) and \(\mathrm{Xe}\) have - comparable ionisation energies.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- For the reaction, \(\mathrm{H}_2(g)+\mathrm{I}_2(g) \rightleftharpoons 2 \mathrm{HI}(g)\) the position of equilibrium can be shifted to the right byCOMEDK 2022 Easy
- Which of the following is incorrect?COMEDK 2023 Medium
- The complex which does not show optical isomerism isCOMEDK 2022 Medium
- Given below are 4 molecular species/ions. Identify the species/ion which exhibits diamagnetic nature.
\([\mathrm{A}]=\mathrm{N}_2^{+} \quad[\mathrm{B}]=\mathrm{O}_2^{-} \quad[\mathrm{C}]=\mathrm{B}_2 \quad[\mathrm{D}]=\mathrm{C}_2\)COMEDK 2024 Medium - The following results were obtained during study of the reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g})\). Determine the value of \([\mathrm{X}]\) in \(\mathrm{mol} / \mathrm{L}\)
\(\begin{array}{|c|c|c|c|} \hline \text{Experiment} & \text{[NO] mol/L} & \left[\mathrm{Cl}_2\right] \text{ mol/L} & \text{Initial rate of formation. [NOCl] mol/L/min} \\ \hline \text{I} & 0.2 & 0.2 & 6.0 \times 10^{-3} \\ \hline \text{II} & 0.2 & 0.4 & 2.4 \times 10^{-2} \\ \hline \text{III} & 0.4 & 0.2 & 1.2 \times 10^{-2} \\ \hline \text{IV} & X & 0.6 & 1.35 \times 10^{-1} \\ \hline \end{array}\)COMEDK 2025 Medium - Which of the following chemicals does not liberate hydrogen gas on reaction with aluminium metal?COMEDK 2015 Hard
More PYQs from COMEDK
- If the area of the auxillary circle of the ellipse \(\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1(a>b)\) is twice the area of the ellipse, then the eccentricity of the ellipse isCOMEDK 2020 Medium
- \(\int \sqrt{2ax - x^2}\ dx =\)COMEDK 2026 Medium
- Thomas slag isCOMEDK 2013 Easy
- The degree of the differential equation \(\left(1+\left(\frac{d y}{d x}\right)^{2}\right)^{3 / 4}=\left(\frac{d^{2} y}{d x^{2}}\right)^{1 / 3}\) isCOMEDK 2013 Easy
- In Young's double slit experiment, if monochromatic light used is replaced by white light, thenCOMEDK 2013 Easy
- The current in a simple series circuit is \(5.0 \mathrm{~A}\).
When an additional resistance of \(2.0 \Omega\) is inserted, the current drops to \(4.0 \mathrm{~A}\). The original resistance of the circuit (in \(\Omega\) ) isCOMEDK 2017 Easy