COMEDK · Chemistry · 19. Chemical Kinetics
The following results were obtained during study of the reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_2(\mathrm{~g}) \rightarrow 2 \mathrm{NOCl}(\mathrm{g})\). Determine the value of \([\mathrm{X}]\) in \(\mathrm{mol} / \mathrm{L}\)
\(\begin{array}{|c|c|c|c|} \hline \text{Experiment} & \text{[NO] mol/L} & \left[\mathrm{Cl}_2\right] \text{ mol/L} & \text{Initial rate of formation. [NOCl] mol/L/min} \\ \hline \text{I} & 0.2 & 0.2 & 6.0 \times 10^{-3} \\ \hline \text{II} & 0.2 & 0.4 & 2.4 \times 10^{-2} \\ \hline \text{III} & 0.4 & 0.2 & 1.2 \times 10^{-2} \\ \hline \text{IV} & X & 0.6 & 1.35 \times 10^{-1} \\ \hline \end{array}\)
- A \([X]=0.4\)
- B \([\mathrm{X}]=0.8\)
- C \([\mathrm{X}]=0.3\)
- D \([\mathrm{X}]=0.5\)
Answer & Solution
Correct Answer
(D) \([\mathrm{X}]=0.5\)
Step-by-step Solution
Detailed explanation
The rate law for the reaction \(2 \mathrm{NO}(g) + \mathrm{Cl}_2(g) \rightarrow 2 \mathrm{NOCl}(g)\) is given by \(r = k[\mathrm{NO}]^a[\mathrm{Cl}_2]^b\). From experiment I and II, keeping \([\mathrm{NO}]\) constant at \(0.2 \text{ mol/L}\):…
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