COMEDK · Chemistry · 7. Chemical Equilibrium
The equilibrium constants for the reactions \(a, b\), and \(c\) are as given:
a) \(\mathrm{N}_2+3 \mathrm{H}_2=2 \mathrm{NH}_3: \mathbf{K}_1\)
b) \(\mathrm{N}_2+\mathrm{O}_2=2 \mathrm{NO}: \mathrm{K}_2\)
c) \(2 \mathrm{H}_2+\mathrm{O}_2=2 \mathrm{H}_2 \mathrm{O}: \mathbf{K}_3\)
What would be the Equilibrium constant for the reaction:
\(4 \mathrm{NH}_3+5 \mathrm{O}_2=4 \mathrm{NO}+6 \mathrm{H}_2 \mathrm{O} ; \mathbf{K}_{\mathbf{x}}\)
- A \(\mathbf{K}_{\mathbf{x}}=\mathrm{K}_1{ }^2 / \mathrm{K}_2 \mathrm{~K}_3{ }^3\)
- B \(\mathbf{K}_{\mathbf{x}}=\mathrm{K}_1 / \mathrm{K}_2 \mathrm{~K}_3\)
- C \(\mathbf{K}_{\mathbf{x}}=\mathrm{K}_2{ }^2 \mathrm{~K}_3{ }^3 / \mathrm{K}_1{ }^2\)
- D \(\mathbf{K}_{\mathbf{x}}=1 / \mathbf{K}_1{ }^2+\mathbf{K}_2{ }^2+\mathrm{K}_3{ }^3\)
Answer & Solution
Correct Answer
(C) \(\mathbf{K}_{\mathbf{x}}=\mathrm{K}_2{ }^2 \mathrm{~K}_3{ }^3 / \mathrm{K}_1{ }^2\)
Step-by-step Solution
Detailed explanation
Correct option is C.
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