COMEDK · Chemistry · 6. Thermodynamics (C)
The enthalpy of neutralisation of \(\mathrm{HCl}\) and \(\mathrm{NaOH}\) is \(x \mathrm{~kJ}\). The heat evolved, when \(500 \mathrm{~mL}\) of \(2 \mathrm{~N} \mathrm{HCl}\) is mixed with \(250 \mathrm{~mL}\) of \(4 \mathrm{~N} \mathrm{NaOH}\) will be
- A \(x\)
- B \(\frac{x}{2}\)
- C \(\frac{x}{4}\)
- D \(\frac{2 x}{3}\)
Answer & Solution
Correct Answer
(A) \(x\)
Step-by-step Solution
Detailed explanation
Number of gram equivalent of \(\mathrm{HCl}\) \[ =N_{1} V_{1}=2 \times \frac{500}{1000}=1 \] No. of gram equivalent of \(\mathrm{NaOH}\) \[ =N_{2} V_{2}=4 \times \frac{250}{1000}=1 \] \(\because\) Both NaOH and MCI are one gram equivalents. \(\therefore\) Heat evolved during…
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