COMEDK · Chemistry · 6. Thermodynamics (C)
The enthalpies of formation of \(\mathrm{Al}_{2} \mathrm{O}_{3}\) and \(\mathrm{Cr}_{2} \mathrm{O}_{3}\) are \(-1596 \mathrm{~kJ}\) and \(-1134 \mathrm{~kJ}\) respectively. \(\Delta H\) for the reaction,
\(2 \mathrm{Al}+\mathrm{Cr}_{2} \mathrm{O}_{3} \longrightarrow 2 \mathrm{Cr}+\mathrm{Al}_{2} \mathrm{O}_{3}\) is
- A \(-2730 \mathrm{~kJ}\)
- B \(-462 \mathrm{~kJ}\)
- C \(-1365 \mathrm{~kJ}\)
- D \(+2730 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(B) \(-462 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\(\Delta H_{\text {Reaction }}=\left(\Delta H_{f}\right)_{\text {Product }}-\left\langle\Delta H_{f}\right)_{\text {Reactant }}\) \(=-1596-(-1134)=-462 \mathrm{~kJ}\)
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