COMEDK · Chemistry · 5. States of Matter
The density of a gas \(A\) is thrice that of a gas \(B\) at the same temperature. The molecular weight of gas \(B\) is twice that of \(A\). What will be the ratio of pressure acting on \(B\) and \(A\) ?
- A \(\frac{1}{4}\)
- B \(\frac{7}{8}\)
- C \(\frac{2}{5}\)
- D \(\frac{1}{6}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{6}\)
Step-by-step Solution
Detailed explanation
\(\frac{d}{p}=\frac{M}{R T}\) Let density of gas \(B\) be \(d\). \(\therefore\) Density of gas \(A=3 d\) and let inolecular weight of \(A\) be \(M\). \(\because\) Molecular weight of \(B=2 \mathrm{M}\). Since, \(R\) is a gas constant and \(T\) is same for both gases, so,…
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