COMEDK · Chemistry · 19. Chemical Kinetics
The decomposition of \(\mathrm{PH}_3\) follows first order kinetics. The time required for \(3 / 4^{\text {th }}\) of \(\mathrm{PH}_3\) to decompose is 75.76 s . Calculate the fraction of original amount of \(\mathrm{PH}_3\) which will remain after 2.0 minutes.
- A \(0.111\)
- B \(0.898\)
- C \(0.954\)
- D \(0.354\)
Answer & Solution
Correct Answer
(A) \(0.111\)
Step-by-step Solution
Detailed explanation
For a first order reaction, the rate constant \(k\) is given by \(k = \dfrac{2.303}{t} \log \left( \dfrac{[A]_0}{[A]_t} \right)\). Given that \(3/4\) of \(\mathrm{PH}_3\) decomposes, the remaining amount \([A]_t = [A]_0 - \dfrac{3}{4}[A]_0 = \dfrac{1}{4}[A]_0\). Substituting the…
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