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COMEDK · Chemistry · 19. Chemical Kinetics

The decomposition of \(\mathrm{PH}_3\) follows first order kinetics. The time required for \(3 / 4^{\text {th }}\) of \(\mathrm{PH}_3\) to decompose is 75.76 s . Calculate the fraction of original amount of \(\mathrm{PH}_3\) which will remain after 2.0 minutes.

  1. A \(0.111\)
  2. B \(0.898\)
  3. C \(0.954\)
  4. D \(0.354\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.111\)

Step-by-step Solution

Detailed explanation

For a first order reaction, the rate constant \(k\) is given by \(k = \dfrac{2.303}{t} \log \left( \dfrac{[A]_0}{[A]_t} \right)\). Given that \(3/4\) of \(\mathrm{PH}_3\) decomposes, the remaining amount \([A]_t = [A]_0 - \dfrac{3}{4}[A]_0 = \dfrac{1}{4}[A]_0\). Substituting the…