COMEDK · Chemistry · 1. Some Basic Concepts of Chemistry
The decomposition of a certain mass of \(\mathrm{CaCO}_{3}\) gave \(11.2 \mathrm{dm}^{3}\) of \(\mathrm{CO}_{2}\) gas at \(\mathrm{STP}\). The mass of \(\mathrm{KOH}\) required to completely neutralise the gas is
- A \(56 \mathrm{~g}\)
- B \(28 \mathrm{~g}\)
- C \(42 \mathrm{~g}\)
- D 20 g
Answer & Solution
Correct Answer
(A) \(56 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
Decomposition of \(\mathrm{CaCO}_{3}\) as follows: Neutralisation reaction of \(\mathrm{KOH}\) and \(\mathrm{CO}_{2}\) as follows: \(2 \mathrm{KOH}+\mathrm{CO}_{2} \stackrel{\Delta}{\longrightarrow} \mathrm{K}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O}\) 2 moles 1 mole 1 mole…
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