COMEDK · Chemistry · 24. Coordination Compounds
The 'd' electronic configuration of \(\left[\mathrm{Ru}(\mathrm{en})_3\right] \mathrm{Cl}_2\) and \(\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_2\) respectively are _____ and ____ .
[Given: Atomic number of \(\mathrm{Ru}=44\) and \(\mathrm{Fe}=26\) ]
- A \(t_{2 g}{ }^6 e_g^0 ; t_{2 g}{ }^6 e_g^0\)
- B \(t_{2 g}{ }^6 e_g^0 ; t_{2 g}{ }^4 e_g^2\)
- C \(t_{2 g}{ }^4 e_g^2 ; t_{2 g}{ }^6 e_g^0\)
- D \(t_{2 g}{ }^4 e_g^2 ; t_{2 g}{ }^4 e_g^2\)
Answer & Solution
Correct Answer
(B) \(t_{2 g}{ }^6 e_g^0 ; t_{2 g}{ }^4 e_g^2\)
Step-by-step Solution
Detailed explanation
For \(\left[\mathrm{Ru}(\mathrm{en})_3\right] \mathrm{Cl}_2\), the oxidation state of \(\mathrm{Ru}\) is \(+2\). The atomic number of \(\mathrm{Ru}\) is \(44\), so its electronic configuration is \([\mathrm{Kr}] 4d^7 5s^1\). For \(\mathrm{Ru}^{2+}\), the configuration is…
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