COMEDK · Chemistry · 24. Coordination Compounds
The correct order of spin only magnetic moments among the following is:
[Given: Atomic numbers: \(\mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27\) ]
- A \(\left[\mathrm{MnCl}_4\right]^{2-}>\left[\mathrm{CoCl}_4\right]^{2-}>\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}\)
- B \(\left[\mathrm{MnCl}_4\right]^{2-}>\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}>\left[\mathrm{CoCl}_4\right]^{2-}\)
- C \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}>\left[\mathrm{CoCl}_4\right]^{2-}>\left[\mathrm{MnCl}_4\right]^{2-}\)
- D \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}>\left[\mathrm{MnCl}_4\right]^{2-}>\left[\mathrm{CoCl}_4\right]^{2-}\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{MnCl}_4\right]^{2-}>\left[\mathrm{CoCl}_4\right]^{2-}>\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}\)
Step-by-step Solution
Detailed explanation
For \(\left[\mathrm{MnCl}_4\right]^{2-}\): Mn is in \(+2\) oxidation state (\(d^5\) configuration). Since \(\mathrm{Cl}^{-}\) is a weak field ligand, the electrons remain unpaired. Number of unpaired electrons \(n = 5\). Magnetic moment…
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