COMEDK · Chemistry · 29. Amines
The correct increasing order of basic strength of following amines,
\(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}, \mathrm{NH}_{3},\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}_{6} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) in gaseous state is
- A \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH} < \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} < \mathrm{NH}_{3} < \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\)
- B \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} < \left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH} < \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} < \mathrm{NH}_{3}\)
- C \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} < \mathrm{NH}_{3} < \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} < \left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}\)
- D \(\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH} < \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} < \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} < \mathrm{NH}_{3}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2} < \mathrm{NH}_{3} < \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2} < \left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{NH}\)
Step-by-step Solution
Detailed explanation
Aniline is less basic than ammonia and aliphatic amines due to delocalisation of lone pair of electrons on the benzene ring. Aliphatic amines are stronger bases, than ammonia due to \(+I\)-effect of alkyl group. More the number of alkyl groups stronger is the base. Hence, basic…
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