COMEDK · Chemistry · 18. Electrochemistry
The cathode reaction in the dry cell will be
- A \(\mathrm{Zn}(s) \longrightarrow \mathrm{Zn}^{2+}+2 e^{-}\)
- B \(\mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{--} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3}\)
- C \(\mathrm{Zn}(\mathrm{Hg})+2 \mathrm{OH}^{-} \longrightarrow \mathrm{ZnO}(s)+\mathrm{H}_{2} \mathrm{O}+2 e^{-}\)
- D \(\mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3} \longrightarrow \mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+2 e^{-}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{--} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3}\)
Step-by-step Solution
Detailed explanation
The cathode reaction in dry cell is \[ \mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{-} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3} \]
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