COMEDK · Chemistry · 19. Chemical Kinetics
The Activation energy for the reaction \(A \rightarrow B+C\), at a temperature \(\mathrm{TK}\) was \(0.04606 \mathrm{~RT} \mathrm{~J} / \mathrm{mol}\). What is the ratio of Arrhenius factor to the Rate constant for this reaction?
- A 1.585
- B \(3.2 \times 10^{-2}\)
- C \(1.047 \times 10^{-2}\)
- D 1.047
Answer & Solution
Correct Answer
(D) 1.047
Step-by-step Solution
Detailed explanation
The Arrhenius equation is given by \(k = A e^{-E_a / RT}\), where \(k\) is the rate constant, \(A\) is the Arrhenius factor, \(E_a\) is the activation energy, \(R\) is the gas constant, and \(T\) is the temperature. Given \(E_a = 0.04606 RT\) J/mol, we substitute this into the…
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