COMEDK · Chemistry · 8. Ionic Equilibrium
Solubility product of a salt \(A B\) is \(1 \times 10^{-8} \mathrm{M}^{2}\) in a solution in which the concentration of \(A^{+}\)ions is \(10^{-3} \mathrm{M}\). The salt will precipitate when the concentration of \(B^{-}\)ions is kept
- A between \(10^{-8} \mathrm{M}\) to \(10^{-7} \mathrm{M}\)
- B between \(10^{-7} \mathrm{M}\) to \(10^{-6} \mathrm{M}\)
- C \(>10^{-5} \mathrm{M}\)
- D \( < 10^{-8} \mathrm{M}\)
Answer & Solution
Correct Answer
(C) \(>10^{-5} \mathrm{M}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} K_{\mathrm{sp}} &=10^{-8} \mathrm{M}^{2} \\ K_{\mathrm{sp}} &=\left[A^{+}\right]\left[B^{-}\right] \\ 10^{-8} &=\left(10^{-3}\right)\left[B^{-}\right] \\ {\left[B^{-}\right] } &=10^{-5} \mathrm{M} \end{aligned} \] \(\therefore\) Salt will precipitate, when…
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