COMEDK · Chemistry · 8. Ionic Equilibrium
Solubility product of a salt \(A B\) is \(1 \times 10^{-8}\) in a solution in which concentration of \(A\) is \(10^{-3} \mathrm{M}\). The salt will precipitate when the concentration of \(B\) becomes more than
- A \(10^{-4} \mathrm{M}\)
- B \(10^{-7} \mathrm{M}\)
- C \(10^{-6} \mathrm{M}\)
- D \(10^{-5} \mathrm{M}\)
Answer & Solution
Correct Answer
(D) \(10^{-5} \mathrm{M}\)
Step-by-step Solution
Detailed explanation
\(K_{s p}=[A][B]\) \[ \begin{aligned} 10^{-8} &=10^{-3}[B] \\ {[B] } &=10^{-5} \mathrm{M} \end{aligned} \] \(\therefore\) Salt will precipitate when \([B]>10^{-5}\)
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