COMEDK · Chemistry · 18. Electrochemistry

Resistance of 0.2 M solution of an electrolyte is 50 \(\Omega\). The conductivity of the solution is 1.3 Sm\(^{-1}\). If the resistance of 0.4 M solution of the same electrolyte is 260 \(\Omega\), its molar conductivity is:

A \(625 \times 10^{-4}\ Sm^2mol^{-1}\)
B \(62.5 \times 10^{-4}\ Sm^2mol^{-1}\)
C \(6.25 \times 10^{-3}\ Sm^2mol^{-1}\)
D \(6.25 \times 10^{-4}\ Sm^2mol^{-1}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(6.25 \times 10^{-4}\ Sm^2mol^{-1}\)

Step-by-step Solution

Detailed explanation

The cell constant \(G^*\) is given by the product of conductivity and resistance of the first solution: \(G^* = \kappa_1 \times R_1\) \(G^* = 1.3\ S\ m^{-1} \times 50\ \Omega = 65\ m^{-1}\) The conductivity of the \(0.4\ M\) solution, \(\kappa_2\), is:…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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