COMEDK · Chemistry · 8. Ionic Equilibrium
Pure water is neutral because
- A \(\mathrm{pH}=7\)
- B litmus has no effect
- C it is free from dissolved salts
- D \(\mathrm{pH}=0\)
Answer & Solution
Correct Answer
(A) \(\mathrm{pH}=7\)
Step-by-step Solution
Detailed explanation
Pure water is neutral as it has equal concentration of \(\mathrm{H}^{+}\)and \(\mathrm{OH}^{-}\)ions. It has \(\mathrm{pH}=7\).
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Choose the incorrect statement from the following:
A. Isoelectronic molecules/ions have the same bond order.
B. Dipole moment of \(\mathrm{NH}_3\) is greater than that of \(\mathrm{NF}_3\).
C. The Carbon in Methyl Carbocation is \(\mathrm{sp}^3\) hybridised.
D. The stability of an ionic compound is measured in terms of its lattice enthalpy and not simply based on attaining Octet configuration.COMEDK 2024 Medium - Pick out the correct option
Assertion(A): Mercury is not considered as a transition element
Reason (R): Mercury is a liquidCOMEDK 2026 Medium - The total number of nodes are given byCOMEDK 2021 Easy
- 50 ec of oxalic acid is oxidised by 25 cc of \(0.20 \mathrm{~N} \mathrm{KMnO}\). The mass of oxalic acid present in 500 ce of the solution isCOMEDK 2019 Medium
- Match the structures in Column I with their correct IUPAC names given in Column II.
COMEDK 2025 Medium - Given below are 4 equations showing Molar conductivities at infinite dilution of various electrolytes. Which one of them represents the correct equation?
\(\begin{aligned}
& \left(\Lambda_m^0\right)_{N a B r}-\left(\Lambda_m^0\right)_{N a C l}=\left(\Lambda_m^0\right)_{\mathrm{KCl}}-\left(\Lambda_m^0\right)_{\mathrm{KBr}} \\
& \left(\Lambda_m^0\right)_{\mathrm{HCl}}+\left(\Lambda_m^0\right)_{\mathrm{KOH}}-\left(\Lambda_m^0\right)_{\mathrm{KCl}}=\left(\Lambda_m^0\right)_{\mathrm{H}_2 \mathrm{O}} \\
& \left(\Lambda_m^0\right)_{\mathrm{KBr}}-\left(\Lambda_m^0\right)_{\mathrm{NaBr}}=\left(\Lambda_m^0\right)_{\mathrm{NaBr}}-\left(\Lambda_m^0\right)_{\mathrm{Nal}} \\
& \left(\Lambda_m^0\right)_{N H_4 \mathrm{Cl}}-\left(\Lambda_m^0\right)_{\mathrm{NH}_4 \mathrm{NO}_3}=\left(\Lambda_m^0\right)_{N H_4 \mathrm{Cl}}-\left(\Lambda_m^0\right)_{N H 4 B r}
\end{aligned}\)COMEDK 2024 Medium
More PYQs from COMEDK
- If \(A, B\) and \(C\) are mutually exclusive and exhaustive events of a random experiment such that \(P(B)=\dfrac{3}{2} P(A)\) and \(P(C)=\dfrac{1}{2} P(B)\), then \(P(A \cup C)\) equals toCOMEDK 2023 Easy
- Decomposition of hydrogen peroxide can be prevented by addingCOMEDK 2023 Easy
- A current of 2 A is passed through the primary coil. The total flux linked with the secondary coil, which is closely wound over the primary is \(2000 \times 10^{-6}\) weber. What is the induced emf in the secondary if the current through the primary increases at a rate of \(0.2 \mathrm{As}^{-1}\) ?COMEDK 2025 Easy
- The variation of the stopping potential (\(V_0\)) with the frequency of incident radiation(n) is as given below.
[\(n_0\) - threshold frequency. h- Planck's constant e- electronic charge] then the slope of the graph AB with the frequency axis is:
COMEDK 2026 Easy - PQRS is square of side \(1 \mathrm{~m}\). A charge of \(100 \mu \mathrm{C}\) is placed at the centre of the square. Then the work done to take \(3 \mu \mathrm{C}\) charge from the corner \(\mathrm{P}\) to the corner \(\mathrm{R}\).COMEDK 2023 Medium
- The wave theory of light, in its original form, was first postulated byCOMEDK 2017 Easy