COMEDK · Chemistry · 8. Ionic Equilibrium
\(\mathrm{pH}\) of \(10^{-3} \mathrm{M}\) solution of \(\mathrm{KOH}\) is.
- A 7.01
- B 2
- C 11
- D 9
Answer & Solution
Correct Answer
(C) 11
Step-by-step Solution
Detailed explanation
As \(\mathrm{KOH}\) is a base. \[ \begin{aligned} & \mathrm{pOH}=-\log \left[\mathrm{OH}^{-}\right] \\ & \mathrm{pOH}=-\log \left[10^{-3}\right]=3 \\ & \mathrm{pH}+\mathrm{pOH}=14 \\ & \mathrm{p}_{\mathrm{H}}=14-3=11 \end{aligned} \]
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