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COMEDK · Chemistry · 8. Ionic Equilibrium

\(\mathrm{pH}\) of \(10^{-3} \mathrm{M}\) solution of \(\mathrm{KOH}\) is.

  1. A 7.01
  2. B 2
  3. C 11
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(C) 11

Step-by-step Solution

Detailed explanation

As \(\mathrm{KOH}\) is a base. \[ \begin{aligned} & \mathrm{pOH}=-\log \left[\mathrm{OH}^{-}\right] \\ & \mathrm{pOH}=-\log \left[10^{-3}\right]=3 \\ & \mathrm{pH}+\mathrm{pOH}=14 \\ & \mathrm{p}_{\mathrm{H}}=14-3=11 \end{aligned} \]