COMEDK · Chemistry · 6. Thermodynamics (C)

Ozone is formed by the reaction
\(\text{O}_{2(g)} + \text{O}_{(g)} \rightarrow \text{O}_{3(g)},\ \Delta H = -107.2\ kJ\).
Given O=O bond energy is 498.0 kJ \(\text{mol}^{-1}\), the average bond energy of ozone is:

A \(120.5\ \text{kJ mol}^{-1}\)
B \(520.6\ \text{kJ mol}^{-1}\)
C \(201.8\ \text{kJ mol}^{-1}\)
D \(302.6\ \text{kJ mol}^{-1}\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(302.6\ \text{kJ mol}^{-1}\)

Step-by-step Solution

Detailed explanation

The enthalpy of the reaction is given by the difference between the sum of bond energies of reactants and products. \(\Delta H = \sum \text{BE(reactants)} - \sum \text{BE(products)}\) For the given reaction \(\text{O}_{2(g)} + \text{O}_{(g)} \rightarrow \text{O}_{3(g)}\):…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Ozone is formed by the reaction\(\text{O}_{2(g)} + \text{O}_{(g)} \rightarrow \text{O}_{3(g)},\ \Delta H = -107.2\ kJ\).Given O=O bond energy is 498.0 kJ \(\text{mol}^{-1}\), the average bond energy of ozone is:

Step-by-step Solution

Ozone is formed by the reaction
\(\text{O}_{2(g)} + \text{O}_{(g)} \rightarrow \text{O}_{3(g)},\ \Delta H = -107.2\ kJ\).
Given O=O bond energy is 498.0 kJ \(\text{mol}^{-1}\), the average bond energy of ozone is: