COMEDK · Chemistry · 6. Thermodynamics (C)
One mole of an ideal gas for which \(C_V=\frac{3}{2} R\) is heated reversibly at constant pressure of 1 atm from \(25^{\circ} \mathrm{C}\) to \(100^{\circ} \mathrm{C} . \Delta H\) will be
- A 372.56 cal
- B 3.72 cal
- C 37256 cal
- D 37.2 cal
Answer & Solution
Correct Answer
(A) 372.56 cal
Step-by-step Solution
Detailed explanation
We know that, \(\begin{aligned} & C_P=C_V+R \\ & C_P=\frac{3}{2} R+R=\frac{5}{2} R \end{aligned}\) At constant pressure, heat absorb by one mole of gas \(\left(q_p\right)\)…
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