COMEDK · Chemistry · 24. Coordination Compounds
Observe the given below reaction.
Aqueous \(\mathrm{CuSO}_4 \xrightarrow{\text { Excess } a q \mathrm{KCN}} A \xrightarrow{\mathrm{H}_2 \mathrm{~S}} B\)
A, B respectively are
- A \(\mathrm{K}_3\left[\mathrm{Cu}(\mathrm{CN})_4\right]\), no precipitate
- B \(\mathrm{K}_2\left[\mathrm{Cu}(\mathrm{CN})_4\right]\), no precipitate
- C \(\mathrm{K}_4\left[\mathrm{Cu}(\mathrm{CN})_6\right]\), white ppt.
- D \(\mathrm{K}_2\left[\mathrm{Cu}(\mathrm{CN})_4\right]\), black precipitate
Answer & Solution
Correct Answer
(A) \(\mathrm{K}_3\left[\mathrm{Cu}(\mathrm{CN})_4\right]\), no precipitate
Step-by-step Solution
Detailed explanation
The complete reaction is as follow. As \(\mathrm{CN}^{-}\)is a strong ligand, the complex formed is highly stable and does not dissociate to give \(\mathrm{Cu}^{+}\)ions. However, no precipitate of CuS is formed when \(\mathrm{H}_2 \mathrm{~S}\) gas is passes through solution.
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