COMEDK · Chemistry · 23. d and f Block Elements
Match the metals in Column II with their characteristic properties given in Column I.
\(\begin{array}{|c|l|c|c|} \hline & \text { Properties } & & \text { Metals } \\ \hline \text { A } & \text { Lanthanoid with low value of } 3^{\text {rd }} \text { ionisation enthalpy. } & P & V \\ \hline \text { B } & \text { f-Block element with electronic configuration }[\mathrm{Rn}] 6 \mathrm{~d}^2 7 \mathrm{~s}^2 & Q & G d \\ \hline \text { C } & 3 \mathrm{~d} \text {-series metal whose } \mathrm{M}^{3+}{ }_{(\mathrm{aq})} \text { is colourless. } & R & T h \\ \hline \text { D } & 3 \mathrm{~d} \text {-series metal with highest } \Delta \mathrm{H}_{(\text {atomisation })} & S & S c \\ \hline \end{array}\)
- A \(\mathrm{A}=\mathrm{S} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{Q} \quad \mathrm{D}=\mathrm{P}\)
- B \(\mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{P}\)
- C \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{Q} \quad \mathrm{C}=\mathrm{P} \quad \mathrm{D}=\mathrm{S}\)
- D \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{Q} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{P}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{A}=\mathrm{Q} \quad \mathrm{B}=\mathrm{R} \quad \mathrm{C}=\mathrm{S} \quad \mathrm{D}=\mathrm{P}\)
Step-by-step Solution
Detailed explanation
A: Gadolinium (Gd) has the electronic configuration \([Xe] 4f^7 5d^1 6s^2\). The removal of the third electron from the \(5d\) orbital is relatively easy because it results in a stable half-filled \(4f^7\) configuration. Thus, Gd has a low third ionisation enthalpy. So, A = Q.…
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