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COMEDK · Chemistry · 23. d and f Block Elements

Match the ions given in Column I with their characteristic properties given in Column II.

S.No.Column IS.No.Column II
A\(Cr^{2+}\)PStable in aqueous medium and has magnetic moment equal to 5.92 BM.
B\(Cu^+\)QOnly stable oxidation state and does not act as reducing agent.
C\(Mn^{2+}\)RIs a good reducing agent due to attainment of stable \(d^3\) configuration.
D\(Sc^{3+}\)SUnstable in aqueous medium and readily disproportionates.

  1. A \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S}\) \(\quad \mathrm{C}=\mathrm{P}\) \(\quad \mathrm{D}=\mathrm{Q}\)
  2. B \(A=Q\) \(\quad B=P\) \(\quad \mathrm{C}=\mathrm{S}\) \(\quad D=R\)
  3. C \(A = S\) \(\quad B=R\) \(\quad \mathrm{C}=\mathrm{P}\) \(\quad D=Q\)
  4. D \(A=S\) \(\quad B=R\) \(\quad C=Q\) \(\quad \mathrm{D}=\mathrm{P}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{A}=\mathrm{R} \quad \mathrm{B}=\mathrm{S}\) \(\quad \mathrm{C}=\mathrm{P}\) \(\quad \mathrm{D}=\mathrm{Q}\)

Step-by-step Solution

Detailed explanation

For \(\mathrm{Cr}^{2+}\), the electronic configuration is \([Ar]3d^4\). It acts as a strong reducing agent because it gets oxidized to \(\mathrm{Cr}^{3+}\) (\([Ar]3d^3\)), which has a stable half-filled \(t_{2g}\) subshell in octahedral fields. Thus, A matches R. For…