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COMEDK · Chemistry · 26. Alcohols Phenols and Ethers

Match reactions in Column I with the corresponding products formed as given in Column II.
Column IColumn II
A. \(\text{C}_6\text{H}_5\text{N}_2^+\ \text{Cl}^- + \dfrac{\text{H}_2\text{O}}{warm} \rightarrow\)P. p–Bromophenol
B. \(\text{C}_6\text{H}_5\text{OH} + \dfrac{\text{Br}_2\ \text{in}\ \text{CS}_2}{273K} \rightarrow\)Q. 2,4,6–Tribromophenol
C. \(\text{C}_6\text{H}_5\text{OH} + \dfrac{(i)\ \text{CHCl}_3 + \text{NaOH}(aq)}{(ii)\ \text{HCl}} \rightarrow\)R. Phenol
D. \(\text{C}_6\text{H}_5\text{OH} + \text{Br}_2\ (aq) \rightarrow\)S. 2–Hydroxybenzaldehyde

  1. A A - S    B - R    C - Q    D - P
  2. B A - R    B - P    C - S    D - Q
  3. C A - Q    B - R    C - S    D - P
  4. D A - Q    B - P    C - S    D - R
Verified Solution

Answer & Solution

Correct Answer

(B) A - R    B - P    C - S    D - Q

Step-by-step Solution

Detailed explanation

Reaction A: Warming benzene diazonium chloride with water yields phenol. Thus, A matches with R. Reaction B: Bromination of phenol in a non-polar solvent like \(CS_2\) at low temperature (\(273\) K) yields monobromophenols, primarily p-bromophenol as the major product. Thus, B…