COMEDK · Chemistry · 17. Solutions
\(\mathrm{K}_{\mathrm{H}}\) for \(\mathrm{O}_2\) at \(293 \mathrm{~K}\) is \(34.86 \mathrm{~kbar}\). What should be the partial pressure of \(\mathrm{O}_2\) gas so that it has a solubility of \(0.08 \mathrm{~g} / \mathrm{L}\) in water at \(293 \mathrm{~K}\) ? (Density of solution \(=1 \mathrm{~g} / \mathrm{ml}\))
- A 15680 bar
- B 156.8 bar
- C 1.569 bar
- D 156.8 \(\times\) 10\(^{-5}\) bar
Answer & Solution
Correct Answer
(C) 1.569 bar
Step-by-step Solution
Detailed explanation
Henry's Law states that \(P = K_{H} \times x\), where \(P\) is the partial pressure of the gas, \(K_{H}\) is Henry's constant, and \(x\) is the mole fraction of the gas in the solution. Given solubility of \(O_{2} = 0.08 \text{ g/L}\). The molar mass of \(O_{2}\) is…
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