COMEDK · Chemistry · 18. Electrochemistry
In the reaction,
\(F e_{(a q)}^{2+}+A g_{(a q)}^{+} \rightarrow F e_{(a q)}^{3+}+A g_{(s)}\)
The standard emf \(\left(\mathrm{E}^{\circ}\right)\) of the cell is:
\(\left[\right.\) Given: \(\left.E_{\mathrm{Ag}^{+} / \mathrm{Ag}}^o=a V ; \quad E_{\mathrm{Fe}^{2+} / \mathrm{Fe}}^o=b V ; E_{\mathrm{Fe}^{3+} / \mathrm{Fe}}^o=c V\right]\)
- A a - b
- B a + b - c
- C a - c
- D a + 2b - 3c
Answer & Solution
Correct Answer
(D) a + 2b - 3c
Step-by-step Solution
Detailed explanation
Oxidation (Anode): \(Fe^{2+} \to Fe^{3+} + e^-\) Reduction (Cathode): \(Ag^+ + e^- \to Ag\) \(E°_{cell} = E°_{cathode} - E°_{anode} = E°_{Ag^+/Ag} - E°_{Fe^{3+}/Fe^{2+}}\) Finding \(E°_{Fe^{3+}/Fe^{2+}}\) using Gibbs free energy: Reaction 1: \(Fe^{2+} + 2e^- \to Fe\),…
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