COMEDK · Chemistry · 9. Redox Reactions
In the reaction,
\(2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \rightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-}\)
- A \(\mathrm{I_2}\) is a reducing agent
- B \(\mathrm{I}_2\) get oxidised to \(\mathrm{I}^{-}\)
- C \(\mathrm{S}_2 \mathrm{O}_3^{2-}\) gets oxidised to \(\mathrm{S}_4 \mathrm{O}_6^{2-}\)
- D \(\mathrm{S}_2 \mathrm{O}_3^{2-}\) gets reduced to \(\mathrm{S}_4 \mathrm{O}_6^{2-}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{S}_2 \mathrm{O}_3^{2-}\) gets oxidised to \(\mathrm{S}_4 \mathrm{O}_6^{2-}\)
Step-by-step Solution
Detailed explanation
Correct option is C.
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