COMEDK · Chemistry · 7. Chemical Equilibrium

In the equilibrium, \(A B \rightleftharpoons A+B\), if the equilibrium concentration of \(A\) is double, then equilibrium concentration of \(B\) will be

A half
B twice
C \(\frac{1}{4}\) th
D \(\frac{1}{8}\) th

Verified Solution

Answer & Solution

Correct Answer

(A) half

Step-by-step Solution

Detailed explanation

\(A B \rightleftharpoons A+B\) or \(K=\frac{[A][B]}{[A B]}\) if concentration of \(A\) is doubled, the equilibrium concentration of \(B\) becomes half to maintain \(K\) constant.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Find the correct matches of the substances, given in Column I, from their characteristic properties given in Column II.

S.No.	Column I	S.No.	Column II
W	\( \mathrm{Tl} \)	A	Decomposes steam to form its dioxide and dihydrogen gas.
X	\( \mathrm{CCl}_4 \)	B	Consists of twenty 6 -membered rings and twelve 5 membered rings.
Y	\(\mathrm{Tin}\)	C	+3 oxidation state is highly oxidising.
Z	\( \mathrm{C_{60}} \)	D	Electron precise species, neither acts as electron donor nor as electron acceptor.

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