COMEDK · Chemistry · 9. Redox Reactions
In the conversion of \(\mathrm{Br}_{2}\) to \(\mathrm{BrO}_{3}^{-}\), the oxidation number of Br changes from
- A zero to \(+5\)
- B \(+1\) to \(+5\)
- C zero to \(-3\)
- D \(+2\) to \(+5\)
Answer & Solution
Correct Answer
(A) zero to \(+5\)
Step-by-step Solution
Detailed explanation
The oxidation number of \(\mathrm{Br}\) in \(\mathrm{Br}_{2}\) is zero. The oxidation number of \(\mathrm{Br}\) is \(\mathrm{BrO}_{3}^{-}\) \[ \begin{aligned} x+3 \times(-2) &=-1 \\ x &=-1+6 \\ x &=+5 \end{aligned} \]
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