COMEDK · Chemistry · 16. Solid State
If the distance between \(\mathrm{Na}^{+}\)and \(\mathrm{Cl}^{-}\)ions in sodium chloride crystal is \(x \mathrm{pm}\), the length of the edge of the unit cell is
- A \(\frac{x}{2} \mathrm{pm}\)
- B \(2 x \mathrm{pm}\)
- C \(4 x \mathrm{pm}\)
- D \(\frac{x}{4} \mathrm{pm}\)
Answer & Solution
Correct Answer
(B) \(2 x \mathrm{pm}\)
Step-by-step Solution
Detailed explanation
In fcc unit cell of \(\mathrm{NaCl}, \mathrm{Na}^{+}\)ion is present at edge centre and \(\mathrm{Cl}^{-}\)ion is present at corner. \(\therefore\) Edge length, \(a=2 r^{+}+2 r^{-}\) \(\therefore \quad a=2\left(r^{+}+r^{-}\right)\) \(=2 x\) \(\left[\because x=r^{+}+r^{-}\right]\)
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