COMEDK · Chemistry · 18. Electrochemistry
If electrolysis of water is carried out for a time duration of 2 hours, how much electric current in amperes would be required to liberate \(100 \mathrm{~ml}\) of \(\mathrm{O}_2\) gas measured under standard conditions of temperature and pressure?
- A 0.8616 A
- B 0.2393 A
- C 4.178 A
- D 0.1723 A
Answer & Solution
Correct Answer
(B) 0.2393 A
Step-by-step Solution
Detailed explanation
The electrolysis of water produces oxygen gas at the anode according to the reaction: \(2H_2O(l) \rightarrow O_2(g) + 4H^{+}(aq) + 4e^{-}\). From the stoichiometry of the reaction, \(4\) moles of electrons are required to produce \(1\) mole of \(O_2\) gas. At standard…
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