COMEDK · Chemistry · 6. Thermodynamics (C)
If 2 moles of \(\mathrm{C}_6 \mathrm{H}_6(\mathrm{~g})\) are completely burnt \(4100 \mathrm{~kJ}\) of heat is liberated. If \(\Delta H^{\circ}\) for \(\mathrm{CO}_2(\mathrm{~g})\) and \(\mathrm{H}_2 \mathrm{O}(l)\) are -410 and \(-285 \mathrm{~kJ}\) per mole respectively then the heat of formation of \(\mathrm{C}_2 \mathrm{H}_6(\mathrm{~g})\) is
- A \(-116 \mathrm{~kJ}\)
- B \(-375 \mathrm{~kJ}\)
- C \(-775 \mathrm{~kJ}\)
- D \(-885 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(B) \(-375 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{r} 2 \mathrm{C}_2 \mathrm{H}_6(g)+7 \mathrm{O}_2(g) \longrightarrow 4 \mathrm{CO}_2(g)+6 \mathrm{H}_2 \mathrm{O}(l) ; \\ \Delta H=-4100 \mathrm{~kJ} \end{array}\) Let, \(\Delta H_f^{\circ}\left(\mathrm{C}_2 \mathrm{H}_6\right)=x\),…
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