COMEDK · Chemistry · 26. Alcohols Phenols and Ethers
Identify X and Y formed in the following two reactions.
(i) Decan-1-ol \(\xrightarrow{\text { Jones reagent }} \mathrm{X}\)
(ii). Sodium salt of \(\mathrm{X} \xrightarrow{\mathrm{NaOH} / \mathrm{CaO}, \Delta} \mathrm{Y}\)
- A \(\mathrm{X}=\) Decanoic acid \(\quad \mathrm{Y}=\) Nonane
- B \(X=1-\) Methoxy nonane \(\quad Y=\) Octane.
- C \(X=\) Decan -2 -one \(\quad Y=\) Octane
- D \(\mathrm{X}=\) Octanoic acid \(\quad \mathrm{Y}=\) Heptane.
Answer & Solution
Correct Answer
(A) \(\mathrm{X}=\) Decanoic acid \(\quad \mathrm{Y}=\) Nonane
Step-by-step Solution
Detailed explanation
Decan-1-ol is a primary alcohol with the formula \(CH_{3}(CH_{2})_{8}CH_{2}OH\). Jones reagent (\(CrO_{3} / H_{2}SO_{4}\)) is a strong oxidizing agent that oxidizes primary alcohols directly to carboxylic acids. Therefore, the oxidation of decan-1-ol yields decanoic acid…
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