COMEDK · Chemistry · 19. Chemical Kinetics
Identify the correct values to be plotted in the graph, the slope of which can be used to determine the activation energy of a reaction.
- A \(\dfrac{\ln k}{T}\ vs\ T\)
- B \(\ln k\ vs\ T\)
- C \(\ln k\ vs\ \dfrac{1}{T}\)
- D \(\dfrac{T}{\ln k}\ vs\ \dfrac{1}{T}\)
Answer & Solution
Correct Answer
(C) \(\ln k\ vs\ \dfrac{1}{T}\)
Step-by-step Solution
Detailed explanation
According to the Arrhenius equation: \(k = A e^{-E_a / RT}\) Taking the natural logarithm on both sides: \(\ln k = \ln A - \dfrac{E_a}{RT}\) This equation represents a straight line of the form \(y = mx + c\), where \(y = \ln k\) and \(x = \dfrac{1}{T}\). Plotting \(\ln k\)…
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