COMEDK · Chemistry · 1. Some Basic Concepts of Chemistry
How many molecules of CO\(_2\)(g) are obtained on reaction of 24 grams of methane with 4moles of oxygen?
- A \(6.022 \times 10^{23}\)
- B \(9.033 \times 10^{23}\)
- C \(3.011 \times 10^{23}\)
- D \(12.044 \times 10^{23}\)
Answer & Solution
Correct Answer
(B) \(9.033 \times 10^{23}\)
Step-by-step Solution
Detailed explanation
The balanced chemical equation for the combustion of methane is: \(CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)\) Molar mass of \(CH_4 = 16 \text{ g/mol}\) Moles of \(CH_4 = \dfrac{24}{16} = 1.5 \text{ moles}\) Moles of \(O_2\) given \(= 4 \text{ moles}\) From the…
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