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COMEDK · Chemistry · 6. Thermodynamics (C)

Given the bond enthalpies of \(\mathrm{N} \equiv \mathrm{N}\) is \(946 \mathrm{~kJ} / \mathrm{mol}\). \(\mathrm{H}-\mathrm{H}\) is \(435 \mathrm{~kJ} / \mathrm{mol}, \mathrm{N}-\mathrm{N}\) is \(159 \mathrm{~kJ} / \mathrm{mol}\) and \(\mathrm{N}-\mathrm{H}\) is \(389 \mathrm{~kJ} / \mathrm{mol}\), heat of formation of hydrazine in the gas phase (in \(\mathrm{kJ} / \mathrm{mol}\)) is

  1. A 101
  2. B 404
  3. C 798
  4. D 1268
Verified Solution

Answer & Solution

Correct Answer

(A) 101

Step-by-step Solution

Detailed explanation

The reaction to form hydrazine is as follows \(\mathrm{N}_2(g)+2 \mathrm{H}-\mathrm{H}(\mathrm{~g}) \longrightarrow \mathrm{N}_2 \mathrm{H}_4(g)\)…