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COMEDK · Chemistry · 18. Electrochemistry

Given that molar conductances for \(\mathrm{Ba}(\mathrm{OH})_{2}\), \(\mathrm{BaCl}_{2}\) and \(\mathrm{NH}_{4} \mathrm{Cl}\) are \(523.28,280.0\) and \(129.8\) \(\Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\) respectively. What is the molar conductivity \(\left(\Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\right)\) of \(\mathrm{NH}_{4} \mathrm{OH}\) ?

  1. A \(502.88\)
  2. B \(251.44\)
  3. C \(1005.76\)
  4. D \(209.42\)
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Answer & Solution

Correct Answer

(B) \(251.44\)

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Detailed explanation

According to Kohlrausch law of independent migration of ions, the molar conductivity of an electrolyte at infinite dilution is the sum of the molar conductivities of its constituent ions. The given molar conductivities are:…
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