COMEDK · Chemistry · 18. Electrochemistry
Given below are 4 equations showing Molar conductivities at infinite dilution of various electrolytes. Which one of them represents the correct equation?
\(\begin{aligned}
& \left(\Lambda_m^0\right)_{N a B r}-\left(\Lambda_m^0\right)_{N a C l}=\left(\Lambda_m^0\right)_{\mathrm{KCl}}-\left(\Lambda_m^0\right)_{\mathrm{KBr}} \\
& \left(\Lambda_m^0\right)_{\mathrm{HCl}}+\left(\Lambda_m^0\right)_{\mathrm{KOH}}-\left(\Lambda_m^0\right)_{\mathrm{KCl}}=\left(\Lambda_m^0\right)_{\mathrm{H}_2 \mathrm{O}} \\
& \left(\Lambda_m^0\right)_{\mathrm{KBr}}-\left(\Lambda_m^0\right)_{\mathrm{NaBr}}=\left(\Lambda_m^0\right)_{\mathrm{NaBr}}-\left(\Lambda_m^0\right)_{\mathrm{Nal}} \\
& \left(\Lambda_m^0\right)_{N H_4 \mathrm{Cl}}-\left(\Lambda_m^0\right)_{\mathrm{NH}_4 \mathrm{NO}_3}=\left(\Lambda_m^0\right)_{N H_4 \mathrm{Cl}}-\left(\Lambda_m^0\right)_{N H 4 B r}
\end{aligned}\)
- A Equation 4
- B Equation 1
- C Equation 2
- D Equation 3
Answer & Solution
Correct Answer
(C) Equation 2
Step-by-step Solution
Detailed explanation
Using Kohlrausch's law, expanding Equation 2 LHS: \((A^0_m)_{HCl} + (A^0_m)_{KOH} - (A^0_m)_{KCl}\) \(= [\lambda^0(H^+) + \lambda^0(Cl^-)] + [\lambda^0(K^+) + \lambda^0(OH^-)] - [\lambda^0(K^+) + \lambda^0(Cl^-)]\) \(= \lambda^0(H^+) + \lambda^0(OH^-)\) \(= (A^0_m)_{H_2O}\) =…
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